A particle of charge q and mass m moves rectilinearly under the action of an electric field E = α – βx. Here α and β are positive constants and x is the distance from the point where the particle was initially at rest then-
A
Motion of particle is oscillatory
B
Amplitude of the particle is α/β
C
Mean position of the particle is at x = 
D
The maximum acceleration of the particle is 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c, d)
a = 
= 
= 
a = 0 at x = 
Force on the particle is zero at x = 
So, mean position of particle is at x = 
= 
Solve for v = 
v = 0 at x = 0 and x = 
x = 
with mean position at 
.Therefore amplitude of particle is 
.
Maximum acceleration of particle is at extreme position (at x = 0 or x = 
) and α max = 
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