A 10 - kg block is placed on a horizontal surface. The coefficient of friction between them is 0.2. A horizontal force P = 15 N first acts on it in the eastward direction. Later, in addition to P a second horizontal force Q = 20 N acts on it in the northward direction.
east of north.
west of south.
Text Solution
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(a, b, d)
As there are no external forces acting on the ‘A + B’ system, its total momentum is conserved. If the masses of A and B are 2m and 2 respectively, and v is the final common velocity, mu = (m + 2m) v or v = u/3.
Work done against friction = loss in KE = 
mu 2 - 
(3m) v 2
= 
.
The force of friction between the blocks is μ μ mg.
Acceleration of A (to the right) = a 1 = 
.
Acceleration of B (to the left) = a 2 = 
Acceleration of A relative to B = a 1 – (-a 2 ) = 
.
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