C

Step 1: Identify the voltage across the capacitor. From the diagram, let's assume the potential difference across the capacitor is given as \( V \) volts.

Step 2: Use the formula for charge on a capacitor, which is given by:
$$ Q = C \cdot V $$
where \( Q \) is the charge, \( C \) is the capacitance (10 µF = \( 10 \times 10^{-6} F \)), and \( V \) is the potential difference.

Step 3: Substitute the values into the formula:
$$ Q = 10 \times 10^{-6} \cdot V $$

If the potential difference \( V \) is 5 volts (as an example), then:
$$ Q = 10 \times 10^{-6} \cdot 5 = 50 \times 10^{-6} C = 50 \mu C$$

Thus, the charge flowing through the capacitor is 50 µC for a voltage of 5 V. Adjust the voltage value according to the information given in the actual diagram.