Consider a resistor of uniform cross section area connected to a battery of internal resistance zero. If the length of the resistor is doubled by stretching it then –
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(b, c)
(Moderate) As the length is double, the cross section area of the wire becomes half, thus the resistance of the wire R = ρ 
becomes four times the previous value. Hence after the wire is elongated the current becomes one fourth. Electric field is potential difference per unit length and hence becomes half the initial value. The power delivered to resistance is p = 
and hence becomes one fourth.
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