Two bulbs consume same power when operated at 200V and 300V respectively. When these bulbs are connected in series across a DC source of 500 V, then –
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(b, c)
P = V 2 /R ∴ R = V 2 /P or R ∝ V 2
i.e. 
= 
= 4/9
When connected in series, potential drop is in the ratio of their resistance. So 
Now, P = I 2 R or P ∝ R (in series I is the same)
or 
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