Home Physics Fluid Mechanics Mix In a certain experiment, we are investigatin…
Physics Fluid Mechanics Mix Comprehension (MCQ)

In a certain experiment, we are investigating the retarding force that a fluid exerts on an object moving through it. We guess that the size of the object is a factor, so we include A, the cross-sectional area, in an equation. The relative velocity between the object and the fluid is a factor v, as well as the density of the fluid ρ . So we guess F = k ρ m A n v P

where k is a proportionality constant with some appropriate units. Before we run the experiment, we do not know the values of the exponents m, n and p. The chart gives the data for a certain fluid.

Experiment

Object

A (cm2)

V(m/s)

F(N)

1.

Cock ball

1.5

7.0

0.020

2.

Cock ball

1.5

3.5

0.005

3.

Steel ball

1.5

3.5

0.005

4.

Steel ball

3.0

3.5

0.010

5.

Steel ball

4.5

3.5

0.015

6.

Steel ball

3.0

14.0

0.160

(i) Which pair of experiment could be used to determine n?

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Ans.

(i)

Sol. In order to determine n, we need two experiments where everything stays the same except for the area, so that we can investigate the results of a change in area. As for choice A, the object changes and the area does not, so that is out. In choice B, area changes from 1.5 to 3.0 cm 2 , and nothing else changes, so B is correct. Choice is incorrect because the velocity is the only thing that changes. In choice D, both A and b change, so we would not be able to tell how much change in F is due to A and how much is due to v.

(ii)

Sol. In the previous solution. We realized that experiments 4 and 6 have the property that all the input variables stay the same except for velocity v, which increases by a factor of 16, which means that p must be 2. That is, if p is 2, then an increase by a factor of 4 in v results in an increase by a factor of 4 2 in the force.

(iii)

Sol. As for choice A, experiments 1 and 2 could be used to determine p, since the velocity changes and nothing else does. Once p is determined, k can be determined by substituting in values from either experiment 1 or 2. Thus experiments 1 and 2 are sufficient. We can exclude choices B and C (not minimum sets). As for choice D, there is not enough information to obtain p or k.

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