n drops of a liquid, each with surface energy E, join to fo…

Physics Fluid Mechanics Mix MCQ (Single Correct)

n drops of a liquid, each with surface energy E, join to form a single drop. What happens?

Some energy will be released in the process.

Some energy will be absorbed in the process.

The energy released or absorbed will be E (n - n 2/3 ).

The energy released or absorbed will be nE [2 2/3 - 1].

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(a, c)

Let S = surface tension = surface energy per unit area,

r = radius of each small drop, R = radius of a single drop.

n × 4/3 π π r 3 = 4/3 π π R 3 or R = rn 1/3

Initial surface energy = E i = n × 4 π π r 2 × S = nE.

Final surface energy = E f = 4 π π R 2 S = 4 π π r 2 n 2/3 . S = n 2/3 E.

energy released = E i – E f = E(n – n 2/3 ).

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