A stick is tied to the floor of the water tank with a string as shown in the figure. The length of stick is 2m. Area of cross-section of stick is10 –3 m 2 . Specific gravity of stick is 0.25. Take g = 10m/s 2 . Then –
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c, d)
As T + mg = F B ...(1)
Taking torque F B × 
cos θ = mg 
cos θ
∴ F B x = mg λ
Now, F B = (Ax) ρ w g and mg = (A λ ) ρ s g
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A U-tube in which the cross-sectional area of the limb on the left is one quarter, the limb on the …
A wooden block, with a coin placed on its top, floats in water as shown in fig. the distance l and …
A body floats in a liquid contained in a beaker. The whole system as shown falls freely under gravi…
A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the c…
Water is filled in a cylindrical container to a height of 3m. The ratio of the cross-sectional area…
A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the t…