Figure shows a section of tube of varying cross section area. Let A 1 , v 1 , ρ 1 respectively be cross-sectional area, velocity of fluid (an ideal gas) and density of liquid at 1 and corresponding value at ‘2’ be A 2 , v 2 & ρ 2 respectively. Assuming temperature at point 1 and 2 to be same –
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c, d)
Bernoulli’s equation for compressible and non-viscous fluid
= constant
Temperature and height is same at 1 and 2
⇒ v 1 = v 2
⇒ A 1 v 1 < A 2 v 2
Also, mass conservation ⇒ A 1 v 1 ρ 1 = A 2 v 2 ρ 2
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