A large tank is filled with water (density = 10 3 kg/m 3 ). A small hole is made at a depth 10 m below water surface. The range of water issuing out of the hole is R on ground. What extra pressure (in atm) must be applied on the water surface so that the range becomes 2R: (take 1 atm = 10 5 Pa and g = 10 m/s 2
Text Solution
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(3atm)
Range will become twice of velocity of efflux becomes twice. Now as,
v = 
Therefore, h should become 4 times or 40 m
Thus, an extra pressure equivalent to 30 m of water should be applied.
1 atm = 0.76 × 13.6 m of water
= 10.336 m of water
30 m of water 
3.0 atm
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