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CGP EDU Academic Team
Published on: September 12, 2026
There are three small holes in the side of a Mariotte's vessel Figure, closed by corks, a, b and c. A tube d, open at both ends, passes through the cork in the neck of the vessel. The level of the water in the Mariotte's vessel is above hole a. The level of the water in the tube d is at the very bottom of the tube, which is on a level with hole b. What will happen if one of the holes a, b or c is unstopped?

Text Solution
Verified by ExpertsThe correct answer is:
A
When one of the holes a, b, or c is unstopped, the water will flow out from that hole due to the difference in pressure and gravitational pull.
Step 1: Understand that a Mariotte's vessel maintains a constant water level as long as the outlet holes are closed.
Step 2: When hole 'a' is unstopped, water will flow out until the water level drops to the level of hole 'a'.
Step 3: For hole 'b', since the water level in tube 'd' is at the bottom, unstopping this hole also allows water to flow out until it matches the level of hole 'b'.
Step 4: Similarly, if hole 'c' is unstopped, water will flow out until the level equilibrates with hole 'c'.
Conclusion: The pressure difference caused by the height of water above the holes drives the flow, which illustrates fluid dynamics principles.
Step 1: Understand that a Mariotte's vessel maintains a constant water level as long as the outlet holes are closed.
Step 2: When hole 'a' is unstopped, water will flow out until the water level drops to the level of hole 'a'.
Step 3: For hole 'b', since the water level in tube 'd' is at the bottom, unstopping this hole also allows water to flow out until it matches the level of hole 'b'.
Step 4: Similarly, if hole 'c' is unstopped, water will flow out until the level equilibrates with hole 'c'.
Conclusion: The pressure difference caused by the height of water above the holes drives the flow, which illustrates fluid dynamics principles.
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