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Physics Fluid Mechanics Mix Subjective Type
Published on: September 12, 2026

A barometer made of a very narrow tube (see figure) is placed at normal temperature and pressure. The coefficient of volume expansion of mercury is 0.00018 per ºC and that of the tube is negligible. The temperature of mercury in the barometer is now raised by 1ºC, but the temperature of the atmosphere does not change. Then the mercury height in the tube remains unchanged.

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Verified by Experts
The correct answer is:
A
Step 1: Understand the scenario: The mercury expands when heated, leading to a change in volume. The expansion of the mercury can be expressed using the coefficient of volume expansion.
Step 2: Calculate the change in volume of mercury due to the temperature change. The formula for volume expansion is given by:
$$ \Delta V = V_0 \beta \Delta T $$
where:
$$ \Delta V $$ = change in volume,
$$ V_0 $$ = initial volume,
$$ \beta $$ = coefficient of volume expansion (0.00018 per ºC),
$$ \Delta T $$ = change in temperature (1ºC).
Step 3: The increase in volume will cause a rise in the height of the mercury column. However, since the barometer is in a vacuum, this rise is countered by the atmospheric pressure acting on the mercury surface.
Step 4: Since the tube is very narrow and the increase in mercury height is negligible due to the volume increase being completely balanced by atmospheric pressure, the height of mercury remains unchanged.
Therefore, A.

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