A black body is at a temperature of 2880K. The energy of radiation emitted by this object with wave length between 499 nm and 500 nm is U 1 , between 999 nm and 1000 nm is U 2 and between 1499 nm and 1500 nm is U 3 . Wein constant b=2.88 x 10 6 nmK. Then
Text Solution
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From wine’s Law 
constant. Where T is temperature of black body and 
is wavelength
corresponding to maximum energy of emission.
Energy distribution of blackbody radiation is given below:
(1) 
and 
are not zero because a blackbody emits nearly radiation’s of all wavelengths.
(2) Since 
corresponds lower wavelength and 
corresponds higher wavelength and 
corresponds medium wavelength. Hence 
.
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