The relation between U, P and V for an ideal gas is U = 2 + 3 P V. The gas is –
Text Solution
Verified by ExpertsThe correct answer is:
C
For an adiabatic process dQ = 0 = dU + dW
or 0 = dU + PdV
From the given equation
dU = 3 (PdV + VdP)
∴ 0 = 3 (PdV + VdP) + PdV
or 4P (dV) + 3V (dP) = 0
or 4
= – 3 
On integrating, we get
ln(V 4 ) + ln(P 3 ) = constant
or PV 4/3 = constant
i.e., γ = 
i.e., gas is polyatomic.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If a cylinder containing a gas at high pressure explodes, the gas undergoes
The work done in an adiabatic change in a gas depends only on
In adiabatic expansion
The pressure in the tyre of a car is four times the atmospheric pressure at 300 K. If this tyre sud…
A monoatomic gas is suddenly compressed to of its original volume adiabatically, then the pressur…