Ans.

(i) [D]

(ii) [B]

(iii) [A], [C]

(iv) [E]

Sol.

For any system, the work done is maximum when a Isobaric process is carried as the graph will be parallel to the volume axis.

So, → (S).

In an isothermal process, dT = 0 and

dW = 2.303 nRT log

or 2.303 nRT log as P i V i = P f V f

So, → (Q).

In adiabatic processes, dQ = 0 and the magnitude of work done which is area below the graph will be more than that of an isochoric process where dW = 0.

So, → (P).

In Isothermal process the variation of P – V will not be as steaper as that of an adiabatic process.

So, → (R)

In Isochoric process, dV = 0. So dW = 0 and → (T).