Figure shows an indicator diagram. During path 1–2–3, 100 c…

Physics Thermodynamics Mix MCQ (Single Correct)

Figure shows an indicator diagram. During path 1–2–3, 100 cal is given to the system and 40 cal worth work is done. During path 1 – 4 –3, the wore done is 10 cal. Then:

heat given to the system during path 1–4–3 is 70 cal

if the system is brought from 3 to 1 along straight-line path 3 –1, work done is worth 25 cal

along straight-line path 3–1 the heat ejected by the system is 85 cal

the internal energy of the system in state 3 is 140 cal above that in state

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(a, b, c)

The critical step is that work in path 1-3 is mean of that for 1-2-3 and 1-4-3 (considering areas).

For 100 – 40 = x – 10 or, x = 70 cal.

It is also correct as half of (40 + 10) is 25 cal.

dU is –60, work is – 25 So, – 60 = dQ – (–25)

or, dQ = – 85 cal

hence, option is also correct.

dU = 100 – 40 = 60 cal

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