A gas is taken through a cyclic process. The change in internal energy along the path from c to a is – 160 J. Heat transferred along the path from a to b is 200 J and 40 J from path b to c. Then -
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(a, b, d)
For cyclic process Q net = W net since Δ U cycle = 0
Q ab + Q bc + Q ca = W ab + W bc + W ca
200 J + 40 J + Q ca = W abc + W ca
240 J + Q ca = W abc + W ca
240 J + Q ca – W ca = W abc
240 – 160 = W abc
W ab + W bc = W abc = 80 J
W ab + 0 = 80 J
W ab = 80 J
W net = W ab + W bc +W ca
Since W ca < 0, W net < 80 J
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