A thermometer of mass 50 gm and specific heat 0.4 cal/gm/ºC reads 10ºC. It is then inserted into1 kg of water and reads 40ºC in thermal equilibrium. The temperature of water before insertion of thermometer in 10 ºC is (Neglect other heat losses).
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(0041)
Neglecting other heat losses
Heat lost by water = Heat gained by
Thermometer
∴ m 1 s 1 ( θ 1 – 40º) = m 2 s 2 (40º – 10º)
m 1 = mass of water
m 2 = mass of thermometer
s 1 = specific heat of water
s 2 = specific heat of thermometer
⇒ θ 1 = 40.6 ºC
≈ 41ºC
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