A calorimeter of negligible heat capacity contains 100 gm water at 40°C. The water cools to 35°C in 5 min.. If water is now replaced by a liquid of same volume as that of water at same initial temperature it cools to 35°C in 2 min. Given sp. heats of water and liquid are 4200 J/kg-°C and 2100 J/kg-°C respectively. Find the density of liquid give answer in….× 100 kg/m 3 . [Assume Newton law of cooling is applicable]
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(8)
(T – T 0 )
dt
ρ λ = 
g/cm 3 = 
= 
= 
×10 2 = 800kg/m 3
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