Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two systems with heat capacities C 1 and C 2 , respectively, interact thermally and come to a common temperature T f . If the initial temperature of system 1 was T 1 , what was the initial temperature of system 2? You may assume that the total energy of the combined systems remains constant.
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: We know that the total energy of the two systems is conserved, which can be expressed mathematically as:
$$ C_1 (T_1 - T_f) + C_2 (T_2 - T_f) = 0 $$
Step 2: Here, \(T_2\) is the initial temperature of system 2. Rearranging the equation gives us:
$$ C_1 (T_1 - T_f) = -C_2 (T_2 - T_f) $$
Step 3: Divide both sides by \(-C_2\) to isolate \(T_2\):
$$ T_2 - T_f = -\frac{C_1}{C_2} (T_1 - T_f) $$
Step 4: Finally, rearranging gives us the expression for \(T_2\):
$$ T_2 = T_f - \frac{C_1}{C_2} (T_1 - T_f) $$
Thus, the initial temperature of system 2 can be expressed in terms of the other variables.
$$ C_1 (T_1 - T_f) + C_2 (T_2 - T_f) = 0 $$
Step 2: Here, \(T_2\) is the initial temperature of system 2. Rearranging the equation gives us:
$$ C_1 (T_1 - T_f) = -C_2 (T_2 - T_f) $$
Step 3: Divide both sides by \(-C_2\) to isolate \(T_2\):
$$ T_2 - T_f = -\frac{C_1}{C_2} (T_1 - T_f) $$
Step 4: Finally, rearranging gives us the expression for \(T_2\):
$$ T_2 = T_f - \frac{C_1}{C_2} (T_1 - T_f) $$
Thus, the initial temperature of system 2 can be expressed in terms of the other variables.
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