Published by:
CGP EDU Academic Team
Published on: September 12, 2026
If 10% of the energy released due to the freezing of 1kg of water at 0 ºC, were utilized to lift a 100 kg man, how high could he be lifted? [ g = 10 m/s 2 , L f = 3.36 × 10 5 J/kg ]
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: Calculate the total energy released during the freezing of 1 kg of water.
The latent heat of fusion (L_f) of water is given as 3.36 × 10^5 J/kg. Therefore, the energy released when freezing 1 kg of water = L_f × mass = 3.36 × 10^5 J/kg × 1 kg = 3.36 × 10^5 J.
Step 2: Calculate 10% of the total energy released.
Energy utilized = 10% of 3.36 × 10^5 J = 0.10 × 3.36 × 10^5 J = 3.36 × 10^4 J.
Step 3: Use the energy to find the height to which a 100 kg man can be lifted.
The work done (W) in lifting an object is given by the formula: W = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Rearranging for height (h), we have: h = W / (mg).
Substituting the values we have: h = (3.36 × 10^4 J) / (100 kg × 10 m/s²) = (3.36 × 10^4 J) / (1000 N) = 33.6 m.
Therefore, the man could be lifted to a height of 33.6 meters.
The latent heat of fusion (L_f) of water is given as 3.36 × 10^5 J/kg. Therefore, the energy released when freezing 1 kg of water = L_f × mass = 3.36 × 10^5 J/kg × 1 kg = 3.36 × 10^5 J.
Step 2: Calculate 10% of the total energy released.
Energy utilized = 10% of 3.36 × 10^5 J = 0.10 × 3.36 × 10^5 J = 3.36 × 10^4 J.
Step 3: Use the energy to find the height to which a 100 kg man can be lifted.
The work done (W) in lifting an object is given by the formula: W = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Rearranging for height (h), we have: h = W / (mg).
Substituting the values we have: h = (3.36 × 10^4 J) / (100 kg × 10 m/s²) = (3.36 × 10^4 J) / (1000 N) = 33.6 m.
Therefore, the man could be lifted to a height of 33.6 meters.
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