B

Step 1: Identify the configuration of resistors in the circuit. The resistors 3 \Omega and 6 \Omega are in series between points A and H, while resistors 4 \Omega and 8 \Omega are in series between points G and B. \
Step 2: Calculate the equivalent resistances of the series components.
The total resistance between A and H (R_{EH}) is:
R_{EH} = 3 \Omega + 6 \Omega = 9 \Omega

The total resistance between G and B (R_{GB}) is:
R_{GB} = 4 \Omega + 8 \Omega = 12 \Omega
Step 3: The 7 \Omega resistor is between points F and D, which are connected to points A and B respectively, in parallel with the series arrangements previously calculated.
Step 4: The equivalent resistance (R_x) for two resistances in parallel is given by: \
\frac{1}{R_x} = \frac{1}{R_{EH} + R_{FB}} + \frac{1}{R_{GB}} = \frac{1}{9 \Omega + 7 \Omega} + \frac{1}{12 \Omega} \
= \frac{1}{16 \Omega} + \frac{1}{12 \Omega}
= \frac{12 + 16}{192} = \frac{28}{192}
Therefore, R_x = \frac{192}{28} \approx 6.857 \Omega (approximately 7 \Omega)
Therefore, the equivalent resistance between points A and B is approximately 7 \Omega.
Therefore, Option B.