A cell has an emf 1.5V. When connected across an external resistance of 2 Ω Ω , the terminal potential difference falls to 1.0V. The internal resistance of the cell is:
Text Solution
Verified by ExpertsThe correct answer is:
C
Internal resistance of the cell is given by
r = 
R
Given fn; E = 1.5V, V = 1.0V, R = 2 Ω Ω
∴ r = 
× 2 = 
× = 1.0 Ω Ω
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