A galvanometer of 50 Ω Ω resistance has 25 divisions. A current of 4 × 10 –4 A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25V, it should be connected with a resistance of:
Text Solution
Verified by ExpertsThe correct answer is:
D
To convert a galvanometer into voltmeter, high resistance should be connected in series with it. Let R is the resistance connected in series with the galvanometer.
i g = 
or R = 
– G
Given, G = 50 Ω Ω ,
i g = 25 × 4 × 10 –4 = 10 –2 A, V = 25V
∴ R = 
– 50 = 2500 – 50 = 2450 Ω Ω
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