From resistances of 100 ohm each are connected in the form of a square. The effective resistance along the diagonal points P R is:

Text Solution
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Here: Resistance of arm PQ (R 1 ) = 100 Ω Ω
Resistance of arm QR (R 2 ) = 100 Ω Ω
Resistance of arm RS (R 3 ) = 100 Ω Ω
Resistance of arm SP (R 4 ) = 100 Ω Ω
Resistance of upper arm R 1 and R 2 are connected in series.
Hence, their resultant resistance
R U = R 1 + R 2 = 100 +100 = 200 Ω Ω
Similarly the resistance of lower half R 3 and R 4 are also connected in series
Hence, their resultant resistance is
R L = R 3 + R 4 = 100 + 100 = 200 Ω Ω
So, equivalent resistance
= 
So, R PR = 100 Ω Ω
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