If the coefficient of friction of a plane inclined at 45º is 0.5, then acceleration of a body sliding freely on it is (g = 9.8m/s2)-
A
4.9 m/s 2
B
9.8 m/s 2
C
m/s 2
D
m/s 2
Text Solution
Verified by ExpertsThe correct answer is:
D
a = g sin 45º – µg cos 45º
a = 
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