A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P, such that the block does not move downward (take g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
A
mg sin θ + 3 = P + friction
mg sin θ + 3 = P + μ mg cos θ .
= P + 0.6 × 10 × 10 × 
20 
+ 3 = P
31.28 = P ⇒ 
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