A prism of refractive index μ and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A, then the value of A in terms of μ is -
A
sin –1 
B
sin –1 
C
2cos –1 
D
cos –1 
Text Solution
Verified by ExpertsThe correct answer is:
C
μ = sin 
, δ m = A
∴ μ = 
= 2cos A/2
∴ A = 2cos –1 ( μ /2)
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