A thin converging lens L 1 forms a real image of an object located far away from the lens as shown in figure. The image is located at a distance 4 λ and has height h. A diverging lens of focal length λ is placed at a distance 2 λ from lens L 1 at A. Another converging lens of focal length 2 λ is placed at a distance 3 λ from lens L 1 at B. The height of final image thus formed is-
A
h
B
4h
C
D
2h
Text Solution
Verified by ExpertsThe correct answer is:
D
For L 2 :
= 
v 2 = –2 λ
For L 3 :
= 
⇒ v 3 = 6 λ
m 2 = 
= 
= –1
m 3 = 
= – 2
Total magnification = m 2 m 3 = 2
∴ Object of height h get magnified two times.
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