Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A point object is moving with a speed of 10 ms–1 in front of a mirror moving with a speed of 3 ms–1 as shown in figure –

Column I | Column II |
(i) velocity of image w.r.t. mirror | [A](5 + 6) – 5 |
(ii) velocity of image w.r.t. object | [B] 5 – 5 |
(iii) velocity of image w.r.t. ground | [C](5+ 3) – 5 |
(iv) velocity of object w.r.t. ground | [D](10+ 6) |
Correct Matrix Matching
Text Solution
Verified by ExpertsThe correct answer is:
C
To solve the problem involving a moving mirror and a moving object, we will use the principles of relative motion.
Step 1: Determine the velocities involved:
- Speed of point object (vobject) = 10 m/s
- Speed of mirror (vmirror) = 3 m/s
Step 2: Calculate the velocity of the image w.r.t. mirror:
The relative velocity of the image with respect to the mirror can be calculated using the formula:
vimage/mirror = vobject + vmirror = 10 m/s + 3 m/s = 13 m/s.
Step 3: Calculate the velocity of image w.r.t. the object:
vimage/object = vmirror - vobject = 3 m/s - 10 m/s = -7 m/s (indicating it moves in the opposite direction).
Step 4: Calculate the velocity of the image w.r.t. the ground:
Assuming the mirror is moving towards the object, we have: vimage/ground = vmirror + vobject = 3 m/s + 10 m/s = 13 m/s.
Step 5: Calculate the velocity of the object w.r.t. ground:
Since the object is also moving, its velocity will be simple: vobject/ground = 10 m/s.
Final Answers:
(i) velocity of image w.r.t. mirror = 13 m/s
(ii) velocity of image w.r.t. object = -7 m/s
(iii) velocity of image w.r.t. ground = 13 m/s
(iv) velocity of object w.r.t. ground = 10 m/s
From the calculations, therefore, the correct answer from Column II that matches is: (C) (5 + 3 - 3) m/s = 5 m/s.
Step 1: Determine the velocities involved:
- Speed of point object (vobject) = 10 m/s
- Speed of mirror (vmirror) = 3 m/s
Step 2: Calculate the velocity of the image w.r.t. mirror:
The relative velocity of the image with respect to the mirror can be calculated using the formula:
vimage/mirror = vobject + vmirror = 10 m/s + 3 m/s = 13 m/s.
Step 3: Calculate the velocity of image w.r.t. the object:
vimage/object = vmirror - vobject = 3 m/s - 10 m/s = -7 m/s (indicating it moves in the opposite direction).
Step 4: Calculate the velocity of the image w.r.t. the ground:
Assuming the mirror is moving towards the object, we have: vimage/ground = vmirror + vobject = 3 m/s + 10 m/s = 13 m/s.
Step 5: Calculate the velocity of the object w.r.t. ground:
Since the object is also moving, its velocity will be simple: vobject/ground = 10 m/s.
Final Answers:
(i) velocity of image w.r.t. mirror = 13 m/s
(ii) velocity of image w.r.t. object = -7 m/s
(iii) velocity of image w.r.t. ground = 13 m/s
(iv) velocity of object w.r.t. ground = 10 m/s
From the calculations, therefore, the correct answer from Column II that matches is: (C) (5 + 3 - 3) m/s = 5 m/s.
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