Polonium
emits α -particles and is converted into
. This reaction is used for producing electric power in a space mission. Po 210 has half life of 138.6 days. Assuming an efficiency of 10%. Now choose correct statement(s) Given : M(Po 210 ) = 209.98264 amu ; M( α ) = 4.0026 amu
M(Pb 206 ) = 205.97440 amu ; 1 amu = 931 MeV energy
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c)
Q = [M(Po 210 ) –M(Pb 206 )– M( α )]931
λ = 
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