A fish F, in the pond is at a depth of 0.8 m from the water surface and is moving vertically upwards with velocity 2 ms –1 . At the same instant a bird B is at a height of 6 m from the water surface and is moving downwards with velocity 3 ms –1 . At this instant both are on the same vertical line as shown in the figure. Which of the following statements are correct ?
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(b, c)
If an object is at a distance x from a plane refracting surface and is viewed normally then it appears at a distance x/µ from the surface where µ is refractive index of that medium (in which it is situated) with respect to the medium in which observer is situated.Suppose height of bird from water surface is x and depth of fish from the surface is y then depth of fish, observed by the bird, will be equal to
r 1 = x + 
… (1)
where µ is refractive index of water with respect to air.
∴ r 1 = 6.60 m
Hence, option is correct.
Height of bird, observed by fish, will be equal to
r 2 = 
+ y … (2)
where μ′ is refractive index of air with respect to water.
Now, μ′ = 
= 
Hence, r 2 = 8.80 m
Hence, option is wrong while is correct
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