A point object is located at a distance 15cm from the pole of a concave mirror of focal length 10cm on its principal axis is moving with a velocity (8 
+ 11 
)cm/s and velocity of mirror is 4 
+ 2 
cm/s. If 
is the velocity of image, then value of | 
| is .........×10 cm/s.
Text Solution
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Ans. 2
Sol. 
= 
+ 
= 
+ 
v = + 30
m = – 
= – 
= –2
= m × 
= (–2) × (9) = –18
v I = v IM + v M
v I = –18 
+ 2 
= – 16 
in vertical direction
= –m 2 × 
= – 4 × (– 4)
v IM = 
= + 16
vI = –16 
+ 4 
= –12 
v = 
= 
= 20cm/s
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