A light ray in medium (RI = 5/3) enters another medium at an angle 30º. The angle in other medium is sin –1 (5/6). How many minimum degrees the incident angle must be increased such that the ray is completely reflected.
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Ans. 7
Sol. 
sin 30º = n . 
⇒ n = 1
sin θ c = 
⇒ θ c = 37º
and so 37 – 30 = 7
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