A certain thin prism is found to produce a minimum deviation of 40º and produces a deviation of 44º when the angle of incidence is either 42º or 62º. The angle of incidence when light undergoes minimum deviation in degree …. × 10 degree.
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Sol.
δ = i + e – A
44° = 42° + 62° – A
44° = 104° – A
A = 104° – 44° = 60º
when deviation is minimum
D = 40°
D = i + e – A
38° = 2i – 60°
100° = 2i
i = 50°
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