Two identical discs are positioned on a vertical axis. The bottom disc is rotating with angular velocity ω 0 . The top disc is initially at rest. It is allowed to fall and sticks to the lower disc. Ratio of K.E. before & after collision.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
⇒ tan θ =
Sol. I ω 0 = 2I ω
(I : M.I. of one disc)
∴ K = 
2 I ω 2 = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Portion AB of the wedge shown in figure is rough and BC is smooth. A solid cylinder rolls without s…
Work done by a force on an rigid object having no rotational motion will be zero, if -
Three identical cylinders rotate with the same angular velocity Ω about parallel central axes. They…
Rolling kinetic energy of a sphere is independent of the radius of the sphere.