Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The volume V versus temperature T graphs for a certain amount of a perfect gas at two pressures P 1 and P 2 are shown in figure. It follows from the graphs that P 1 is greater than P 2 .
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Understand the relationship between pressure, volume, and temperature in the context of the ideal gas law, which states PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
Step 2: As per the graphs, at a constant volume, a higher pressure corresponds to a higher temperature according to the ideal gas law.
Step 3: In the provided graphs, P1 shows a higher volume at a given temperature compared to P2. This indicates that for the same temperature, P1 must be greater since a gas at lower pressure would occupy a larger volume.
Step 4: Thus, it follows that P1 must be greater than P2 based on the characteristics of the graphs.
Therefore, the correct conclusion is that P1 is indeed greater than P2.
Step 2: As per the graphs, at a constant volume, a higher pressure corresponds to a higher temperature according to the ideal gas law.
Step 3: In the provided graphs, P1 shows a higher volume at a given temperature compared to P2. This indicates that for the same temperature, P1 must be greater since a gas at lower pressure would occupy a larger volume.
Step 4: Thus, it follows that P1 must be greater than P2 based on the characteristics of the graphs.
Therefore, the correct conclusion is that P1 is indeed greater than P2.
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