One mole of an ideal gas undergoes a process
P =
. Here P 0 and V 0 are constants. Volume is changed from V = V 0 to V = 3V 0 -
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b)
PV = nRT …(i)
P = 
at V = 3V 0
P = 
Equation (i)
. 3V 0 = nRT

when V = V 0
P =
= 
V 0 = 1 × RT

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