A thin conducting ring of radius R is given a charge
Q. The electric field at the centre O of the ring due to the charge on the part
of the ring is E
The electric field at the center due to the charge on the part ACDB of the ring is

Text Solution
Verified by ExpertsThe correct answer is:
D

The fields at O due to AC and BD cancel each other. The field due to CD is acting in the direction OK and equal in magnitude to E due to 
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