Charges +q and -q are placed at points A and B respectively which are a distance 2L apart, C is the midpoint between A and B 
The work done in moving a charge +q along the semicircle CRD is
Text Solution
Verified by ExpertsThe correct answer is:
C
From figure, 
Potential at C is given by
Potential at D is given by
Comments: Potential at C is zero because the charges are equal and opposite and the distances are the same.
Potential at D due to -q is greater than that at 
, because D is closer to 
. Therefore it is negative.
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