The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length oflenses are
Text Solution
Verified by ExpertsThe correct answer is:
C
: Magnifying power, 
(i)
where 
and 
are the focal lengths of the objective and eyepiece respectively
Also, 
cm 
(ii)
On solving (i) and (ii), we get
cm, 
cm
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