A uniform rod of length ‘
is pivoted at one of its ends on a vertical shaft of negligible radius. When the shaft rotates at angular speed
the rod makes an angle
with it (see figure). To find
equate the rate of change of angular momentum (direction going into the paper)
about the centre of mass (CM) to the torque provided by the horizontal and vertical forces
and
, about the CM. The value of
is then such that :
Text Solution
Verified by ExpertsThe correct answer is:
D

From a rotating frame rod will appear in equilibrium. Net torque about suspension point must be zero.


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