A rod of length 
moves with a constant velocity 
in the magnetic field of a straight long conductor that carries a current 
as shown in the figure. The emf induced in the rod is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
The induced emf between two ends of a segment dx = dE = Bvdx
where B = magnetic field due to straight current carrying
wire
at the segment dx = 
⇒ ⇒ dE = 
The induced emf between the ends of the rod
= E = 
⇒ ⇒ E = 
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