C

Step 1: Determine the angular velocity in radians per second:
1200 rev/min = \frac{1200 \text{ rev}}{1 \text{ min}} \times \frac{2\pi \text{ rad}}{1 \text{ rev}} \times \frac{1 \text{ min}}{60 \text{ s}} = 126.8 \text{ rad/s}
Step 2: Compute the linear velocity (v) at a radius of 25 cm:
v = radius \times angular velocity = 0.25 m \times 126.8 \, rad/s = 31.7 \text{ m/s}
Step 3: Determine the induced EMF (E) using Faraday's law:
E = B \cdot l \cdot v
With B being the magnetic field strength (let's assume it's determined from the field image, say B = 0.5 T), and length of the conductor l = 0.01 m:
E = 0.5 \, T \cdot 0.01 \, m \cdot 31.7 \, \text{m/s} = 0.1585 \text{ V}
Rounding it gives us approximately 0.16 V. Thus the induced voltage is:
Therefore, the answer is option C: 0.16 V.