The binding energy of an electron in the ground state of He is equal to 24.6 eV. The energy required to remove both the electrons is
Text Solution
Verified by ExpertsThe correct answer is:
C
The energy needed to remove one electron from the ground state of 
As the
is now hydrogen like ionization energy

To remove both the electrons, energy needed

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
An -particle of 5 MeV energy strikes with a nucleus of uranium at stationary at an scattering angl…
The ratio of the speed of the electrons in the ground state of hydrogen to the speed of light in va…
In hydrogen atom, electron makes transition from to level. Recoil momentum of the atom will be
A sodium atom is in one of the states labeled 'Lowest excited levels'. It remains in that state for…
An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The ene…
A hydrogen atom in its ground state absorbs 10.2 eV of energy. The orbital angular momentum is incr…