A gas sample of hydrogen like atoms has some atoms in the lowest (ground) energy level A and some atoms in a particular upper (excited) energy level B and there are no atoms in any other energy level. The atoms of the gas make transition to a higher level by absorbing monochromatic light of photon energy 2.7 eV. Subsequently, the atoms emit radiation of only six different photon energies. Some of the emitted photons have energy 2.7 eV. Some have energy more and some have less than 2.7 eV.
(i) Principal quantum number of the initially excited level B is –
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Ans.
(i)
Sol.

n = 2 to 4
(ii)
Sol. 13.6 Z 2
= 2.7
⇒ 13.6 Z 2 = 2.7 ×
eV
= 2.3 × 10 –18 J
(iii)
Sol.
= 13.6 Z 2 
= 13.6 Z 2 × 
= 2.2 × 10 –18 J
E min = 13.6 Z 2 
= 13.6 Z 2 × 
= 1.1 × 10 –19 J
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems