If potential energy in hydrogen atom with electron in ground state is taken to be 13.6 eV, then –
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(a, b, d)
In Ground state
KE = + 13.6 eV, PE = – 27.2 eV,
TE = – 13.6 eV
First excited state
KE = + 3.4 eV, PE = – 6.8 eV, TE = – 3.4 eV
Now PE and TE both will be increased by
13.6 – (– 27.2) = 40.8 eV
KE remains unchanged being independent of reference.
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