Consider ionization energy of a hydrogen atom as W i . Which of the following: electrons, hydrogen ion and helium ion, is more effective in ionizing the hydrogen atom?
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. We assume that a perfectly inelastic collision
occurs between incident particle and hydrogen atom. From conservation of momentum, we can write
mv 0 = (m + m H )u
Initial kinetic energy W 0 =

Final kinetic energy W =
(m + m H )u 2 = 
The decrease in kinetic energy,
W 0 – W =
– 
=
W 0
This decrease in kinetic energy must be equal to
ionization energy.
W i =
(W 0 )
which shows that the greater the mass of the incident
particle, the smaller the fraction of the initial kinetic
energy that can be used for ionization. When an
electron in used, m e << m H , i.e., W i
W 0 , hence, the
initial kinetic energy of the electron is almost completely used for ionization. When a hydrogen atom
is used, the initial kinetic energy must be double that of the electron. For a helium atom,
W 0 – W i =
=
W 0
i.e., the energy must be five times that of the electron.
Note that in a gas-discharge plasma, ionization is
carried out almost by electrons, while ionization by the ions plays an insignificant role.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems