In a nuclear fusion reactor, the reaction occurs in two stages:
Correct Answers for Comprehension Sub-Questions
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Ans.
(i)
Sol. Now, the reaction for the second stage is:
1 T 3 + 1 D 2 → 2 He 4 + 0 n 1 + E 2
∴ Δ m = (3.016049 + 2.014102) – (4.002603 + .008665) = 0.01888u
∴ E 2 = 0.01888 × 931 = 17.587 MeV
(ii)
Sol. Total energy released = E 1 + E 2 = 4.033 + 17.587
= 21.62 MeV
∴ Energy released /deuteron = 
= 7.207 MeV
(iii)
Sol. % of rest mass of deuterium released
= 
= 0.384 %
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Which of the following particles are constituents of the nucleus?
The particles which can be added to the nucleus of an atom without changing its chemical properties…
The neutron was discovered by
The energy equivalent of 1 kilogram of matter is about
Nuclear binding energy is equivalent to
If the binding energy of the deutrium is 2.23 MeV. The mass defect given in a.m.u. is