A charged particle 'q' is shot from infinity towards another charged particle 'Q', which is fixed, with a speed 'v'. It approaches 'Q' upto a closest distance r and then returns. If q were given a speed of '2v', the closest distance of approach would be:
A
r
B
2r
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
By energy conservation
Initially: 0 + 
= 
Finally: 
m (2v)2 = 
So, 
= 
or r´ = 
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